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Jun 12 2008, 04:18 AM
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#11
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Sparkx Group: [HOSTED] Posts: 346 Joined: 11-October 06 From: Dana Point, CA, USA Member No.: 16,496 |
Replying to Feedbacker
I’m confused division by zero is exactly what I said; you just said it in a different way. I said: Any number times 0 is 0. (true use your calculator). You said: Any number divided by 0 is infinity. (also true). Unless there is something I am missing (which might be because I haven't taken calculus in a formal class yet) I think both things are correct. QUOTE still false but wait divide both sides by 0. 7/0=3/0 --> 0=0 This was simply to show a common mistake made by people who often forget basic rules of math, similar to the mistake that people may make in this problem. Thanks, Sparkx |
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Jun 12 2008, 10:55 PM
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#12
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Advanced Member Group: [HOSTED] Posts: 110 Joined: 12-April 08 Member No.: 29,760 |
Haha, I hated Proofs in High school. I think I'll pass at attempting this one.
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Aug 21 2008, 01:52 PM
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#13
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Newbie [ Level 1 ] Group: Members Posts: 0 Joined: 1-November 07 Member No.: 25,869 |
Lol
"Taking positive square root on both sides: 3 - 5/2 = 2 - 5/2 " I'm pretty sure 2 -5/2 isn't positive |
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Aug 18 2008, 10:36 AM
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#14
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Newbie [ Level 1 ] Group: Members Posts: 0 Joined: 1-November 07 Member No.: 25,869 |
A^2 = b^2 does not mean a=b
It could be a=-b as well. Here: (3-5/2)^2=(2-5/2)^2 does not imply 3-5/2 = 2-5/2 In fact, in this case: (3-5/2) = -(2-5/2) -reply by Tirthankar Ghosh |
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Aug 18 2008, 10:32 AM
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#15
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Newbie [ Level 1 ] Group: Members Posts: 0 Joined: 1-November 07 Member No.: 25,869 |
A^2 = b^2 does not mean a=b
It could be a=-b as well. Here: (3-5/2)^2=(2-5/2)^2 does not imply 3-5/2 = 2-5/2 In fact, in this case: (3-5/2) = -(2-5/2) |
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Lo-Fi Version | Time is now: 8th September 2008 - 03:34 AM |