Imagemagick And Php, Help

malum

Nov 3 2008, 02:47 PM

I am running a PHP based web site and have just moved to a Windows server
I can't get Imagemagick to work in PHP.
It works from the command line.

I don't have access to the server other than a simple control panel but I can pass info onto the administrator (who also happens to be my buddy)

running the test page gives me this

Warning: exec() [function.exec]: Unable to fork [convert -version] in D:\home\Customers\virtuallyinsane.com\htdocs\test\test.php on line 11
Version return code is -1

test being

CODE

<html> <head> <title>Test for ImageMagick</title> </head>
<body> 
Warning: exec() [<a href='function.exec'>function.exec</a>]: Unable to fork [convert -version] in D:\home\Customers\virtuallyinsane.com\htdocs\test\test.php on line 11 
Version return code is -1 <ul></ul> </body> </html>

The web based php script has a page to put the path in for Imagemagick but when I do it can't find it, it tell me the path isn't valid (my admin says I shouldn't need the path anyway as it should work from anywhere)

Any help appreciated

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yordan

Nov 3 2008, 06:47 PM

malum,
You first posted this topic in the "tutorial" forum.
Your post is not really a tutorial, looks more like a call for help.

That's why I moved your topic here, where it should most probably have an answer.
By the way, I hate this "cannot fork", looks like a memory access or number of process problem.
Are you sure that your program should run from the command line ? What happens if you try to run it in a window ?

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docduke

Nov 3 2008, 10:48 PM

Here is a test of ImageMagick with more output details:

CODE

<html> <head> <title>Test for ImageMagick</title> </head>
<body> <?
function alist ($array) { //This function prints a text array as an html list.
 $alist = "<ul>";
 for ($i = 0; $i < sizeof($array); $i++) {
 $alist .= "<li>$array[$i]";
 }
 $alist .= "</ul>";
 return $alist;
}
exec("convert -version", $out, $rcode); //Try to get ImageMagick "convert" program version output.
echo "Version return code is $rcode "; //Print the return code: 0 if OK, nonzero if error.
echo alist($out); //Print the output of "convert -version"
?> </body> </html>

It defines a php function "alist" that parses the output of the "version" query and formats it so that a browser can display it.

Copy and paste this code into a .php file and upload it to somewhere that it can be accessed by your (PHP-supporting) web server. Then load it into a browser. It should tell you just about everything that ImageMagick knows about its environment.

I put a tutorial up on it a while ago: How To Find And Test Imagemagick Using Php. If that doesn't help enough, take a look at Basic Usage on the ImageMagick website. By the way, when you do your command-line check, note whether the version number is above or below 5.5.7. There was a significant change in the way it processes arguments at that point.

Hope this helps!

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