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Replying to Y = New Array()


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kelvinmaki

Posted 13 December 2007 - 03:06 PM

Actually declare Y = new Array() is for the top level of the array, not a 2D array. So afterwhich you've declared that, you need to declare another array inside of Y. So like,

Y = new Array();
Y[0] = new Array();
Y[1] = new Array();

Then you are allow to put data into Y[0] array. eg.

Y[0][0] = smith;
Y[0][1] = smith2;
Y[1][0] = john;
Y[1][1] = john2;

Now then you'll have a 2D array. I've gotten error not declaring new Array() for both cases. Hope this help. Cheers

Jeigh

Posted 12 December 2007 - 10:16 PM

As far as I know (I may be wrong, I don't do a lot of javascript work) there are not true 2d arrays in javascript. You can, however, declare one array and then declare elements within that array as arrays which in effect is a multi-dimensional array. The site at http://www.javascrip...twoarray1.shtml can show you an example and I found a bunch more just by quickly googling for '2d arrays in javascript'. It will likely take some playing around but if its important to your design I'm sure you can get something working that will be equivalent to having a 2 dimensional array.

al-rafideen

Posted 12 December 2007 - 05:49 PM

Hi,
I have no problem with one dimension Array. For example:
Y = new Array();
Y[0] = smith;
Y[1] = john;
..
..

My problem is with two dimension Array. For example:
Y[0,0] = smith;
Y[0,1] = john;
..
..
Do you agree to define Y = new Array() with two dimension Array.
Thank you for your help in this matter.

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